The third term in the expansion of \(\frac{z-1}{z+1}\) about the point z = 1 using Taylor’s series is 

1
\(\frac{(z-1)^2}{2}\)
2
\(\frac{(z-1)^2}{4}\)
3
\(\frac{(z-1)^3}{8}\)
4
\(\frac{(z-1)^3}{4}\)

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