Given the following atomic masses

\({ }_{92}^{238} \mathrm{U}\) = 238.05079 u

\({ }_{2}^{4} \mathrm{He}\) = 4.00260 u

\({ }_{90}^{234} \mathrm{Th}\) = 234.04363 u

Calculate the energy released during the alpha decay of \({ }_{92}^{238} \mathrm{U}\).

\(\left(1 \mathrm{u}=931.5 \mathrm{MeV} / \mathrm{C}^{2}\right)\)

1
4.25 MeV
2
6.23 MeV
3
5.75 MeV
4
3.25 MeV

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