If E1 = xy \(\hat{i}\) + 2yz \(\hat{j}\) + 3xz \(\hat{k}\) and E2 = y2 \(\hat{i}\) + (2xy + z2) \(\hat{j}\) + 2yz \(\hat{k}\) then
1
Both are impossible electrostatic fields
2
Both are possible electrostatic fields
3
Only E1 is a possible electrostatic field
4
Only E2 is a possible electrostatic field