From the following half-cell reactions
\(\rm Zn^{2+} + 2e^- \rightarrow Zn(s): E^o_{el}, = -0.76 V\)
\(\rm CuI+e^- \rightarrow Cu(s)+I^-(aq); E^o_{el} =+0.17 V\)
The standard potential E0 of the cell
Zn, Zn2+(1 M) | I-(1M), CuI; Cu
will be
1
-0.42 V
2
+1.10 V
3
+0.42V
4
+0.59 V