Engineering Mathematics Differential Equations

Solution of (x log x)\(\frac{dy}{dx}\) = 2y for y(2) = (log 2)2, is:

1
y = \(\frac{{{{\rm{x}}^2}}}{4}\) (log x)2
2
y = (log 2) · (log x)
3
y =  (log x)2
4
y =  (log x2)

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