Given the following molar conductivities at 25°C, HCl, 426 \(S\ cm^2\ mol^-\) ; NaCl, 126 \(S\ cm^2\ mol^-\); NaC (sodium crotonate), 83 \(S\ cm^2\ mol^-\). What is the ionization constant of crotonic acid? If the conductivity of a 0.001 M crotonic acid solution is 3.83 x 10-5 \(S\ cm^-\)?
1
\(10^{-5}\)
2
\( 1.11\times 10^{-5}\)
3
\( 1.11\times 10^{-2}\)
4
\(0.11\)