The solution of the differential equation \(x \frac{d y}{d x}\) + y = x3y6 is : (where C is an arbitary constant)

1
\(y^{-5} x^{-5}=\frac{5}{2} x^{-2}+C\)
2
\(y^{-5} x^{-2}=\frac{5}{2} x^{-2}+C\)
3
\(y^{-5} x^{-5}=\frac{5}{2} x^{-5}+C\)
4
\(y^{-2} x^{-5}=\frac{5}{2} x^{-2}+c\)

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