Let γ(t) = 3eit, 0 ≤ t ≤ 2π it be the positively oriented circle of radius 3 centred at the origin. The value of λ for which \(\displaystyle\oint_{\gamma} \frac{\lambda}{z-2} d z\) = \(\displaystyle \oint_{\gamma} \frac{1}{z^{2}-5 z+4} d z\) is

1
\(\lambda=\frac{-1}{3} \)
2
λ = 0
3
\(\lambda=\frac{1}{3}\)
4
λ = 1

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