Using the trial function 

\(\psi(x)=\left\{\begin{array}{cc} A\left(a^2-x^2\right), & -a

the ground state energy of a one-dimensional harmonic oscillator is

1
ħω 
2
\(\sqrt{\frac{5}{14}} \hbar \omega\)
3
\(\frac{1}{2} \hbar \omega\)
4
\(\sqrt{\frac{5}{7}} \hbar \omega\)

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