Teaching BPSC 4.0 बिहार उच्च माध्यमिक शिक्षक भर्ती (PGT) Mock Test Physics Center of Mass and Linear Momentum Center of Mass
A rod of length L has non-uniform linear mass density given by \(\rho(x)=\mathrm{a}+\mathrm{b}\left(\frac{x}{\mathrm{~L}}\right)^2\), where a and b are constants and 0 ≤ x ≤ L. The value of x for the centre of mass of the rod is at:
1
\(\frac{3}{4}\left(\frac{2 a+b}{3 a+b}\right) L\)
2
\(\frac{3}{2}\left(\frac{2 a+b}{3 a+b}\right) L\)
3
\(\frac{4}{3}\left(\frac{a+b}{2 a+3 b}\right) L\)
4
\(\frac{3}{2}\left(\frac{a+b}{2 a+b}\right) L\)
5
None of the above/More than one of the above.