Given:
HCl(g) + 40 H2O → HCI (40 H2O); ΔH = -73.0 kJ
HCl(g) + 10 H2O → HCI (10 H2O); ΔH = -69.0 kJ
then integral heat of dilution for two moles of HCI(10 H2O) to HCI (40 H2O) is :
1
-4.5 kJ
2
-3.5 kJ
3
-8.0 kJ
4
More than one of the above
5
None of the above