Probability of 3 students solving a question are \({1\over 2}, {1\over 3}, \) and \({1\over 4}\). Probability to solve the question is:

1
\({1\over 4}\)
2
\({1\over 2}\)
3
\({7\over 12}\)
4
More than one of the above
5
None of the above

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