The area of a triangle is 5 and two of its vertices are A(2, 1), B(3, -2). Then, the third vertex, in 1st quadrant which lies on the line y = x + 3 is
1
\(\left(\frac{7}{2}, \frac{13}{2}\right)\)
2
\(\left(\frac{5}{2}, \frac{5}{2}\right)\)
3
\(\left(\frac{3}{2}, \frac{3}{2}\right)\)
4
More than one of the above
5
None of the above