The average of the squares of the numbers 0, 1, 2, 3, 4, ...., n is

1
\(\rm \frac{1}{2}n(n+1)\)
2
\(\rm \frac{1}{6}n(2n+1)\)
3
\(\rm \frac{1}{6}(n+1)(2n+1)\)
4
More than one of the above
5
None of the above 

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