Chemistry Thermodynamics Thermochemistry

Given: 

HCl(g) + 40 H2O → HCI (40 H2O); ΔH = -73.0 kJ 

HCl(g) + 10 H2O → HCI (10 H2O); ΔH = -69.0 kJ 

then integral heat of dilution for two moles of HCI(10 H2O) to HCI (40 H2O) is : 

1
-4.5 kJ
2
-3.5 kJ
3
-8.0 kJ
4
-2.0 kJ

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