\(AB(g) + \frac 1 2 B_2(g) ⇌ AB_2(g)\) ...i)
\(2AB_2(g) ⇌ 2AB(g) + B_2(g)\) ...ii)
If K1 and K2 are equilibrium constants for the reactions (i) and (ii) respectively, then the relation between K1 and K2 is
1
K1K2 = 1
2
\(K_1 = \frac {K_2} 2\)
3
K2K21 = 1
4
K2 = K21