A ball having kinetic energy KE, is projected at an angle of 60° from the horizontal. What will be the kinetic energy of ball at the highest point of its flight?

1
\(\frac{(\mathrm{KE})}{8}\)
2
\(\frac{(\mathrm{KE})}{4}\)
3
\(\frac{(\mathrm{KE})}{16}\)
4
\(\frac{(\mathrm{KE})}{2}\)

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