If a ≠ 6, b, c satisfy \(\left| {\begin{array}{*{20}{c}} a&{2b}&{2c}\\ 3&b&c\\ 4&a&b \end{array}} \right| = 0,\) then abc =
1
a + b + c
2
0
3
b3
4
ab + bc
If a ≠ 6, b, c satisfy \(\left| {\begin{array}{*{20}{c}} a&{2b}&{2c}\\ 3&b&c\\ 4&a&b \end{array}} \right| = 0,\) then abc =