Quantitative Aptitude Geometry Triangles, Congruence and Similarity

If Δ ABC ~ Δ PQR \(\rm \frac{ar(ABC) } {ar(PQR) }=\rm \frac{ 9} { 4 }\), AB = 18 cm and BC = 15 cm, then QR is equal to

1
10 cm
2
12 cm
3
\(\rm \frac{20 } {3 }cm\)
4
8 cm

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