If 4 tanθ = 3, then what is 

\(\frac{{4\sin \theta - \cos \theta }}{{4\sin \theta + 9\cos \theta }}\)

equal to?

1
\(\frac{1}{2}\)
2
\(\frac{1}{3}\)
3
\(\frac{1}{4}\)
4
\(\frac{1}{6}\)

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