Let ΔABC ~ ΔPQR and \( \frac{\operatorname{ar}(\triangle \mathrm{ABC})}{\operatorname{ar}(\triangle \mathrm{QPR})}=\frac{64}{169} \text { }\) If AB = 10 cm, BC = 7 cm and AC = 16 cm, then PR (in cm) is equal to:

1
13
2
21
3
15
4
26

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