ABCD is a trapezium, where AB is parallel to DC. If AB = 4 cm, BC = 3 cm, CD = 7 cm and DA = 2 cm, then what is the area of the trapezium?

1
\(22\sqrt {\frac{2}{3}} \;c{m^2}\)
2
\(22\sqrt {\frac{3}{2}} \;c{m^2}\)
3
\(22\sqrt 3 \;c{m^2}\)
4
\(\frac{{22\sqrt 2 }}{3}\;c{m^2}\)

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