What mass of 95% pure CaCO3 will be required to neutralise 50 mL of 0.5 MHCl solution according to the following reaction?
CaCO3(s) +2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate upto second place of decimal point]
1
9.50 g
2
1.25 g
3
1.32 g
4
3.65 g