Let A be an n × n matrix from the set of numbers and A3 - 3A2 + 4A - 6I = 0 where I is an n × n unit matrix. If A-1 exists, then

1
A-1 = A - I
2
A-1 = 3A - 6I
3
A-1 = A + 6I
4
\(A^{-1} = \dfrac{1}{6}(A^2 - 3A + 4I)\)

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