Quantitative Aptitude Geometry Triangles

D is a point on side AC of a triangle ABC such that AD = BD, CD = BC and \(\angle BAC\) = 30°. Then, \(\angle ABC\)+ \(\angle BDC\) is equal to :

1
\(120^{\circ}\)
2
\(130^{\circ}\)
3
\(135^{\circ}\)
4
\(150^{\circ}\)

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