The eleventh term in the following sequence:

\(-\frac{3}{2}, \frac{3}{4}, \frac{3}{8}, \frac{3}{16}, -\frac{3}{32},\dots\) is :

1
\(\frac{3}{1024}\)
2
\(-\frac{3}{1024}\)
3
\(\frac{3}{1048}\)
4
\(-\frac{3}{2048}\)

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