Direction: In the following question two equations numbered I and II are given. You have to solve both the equations and give answers:
I) x2 − x − (2√3)2 = 0
II) y2 − 6y − 16 = 01
if x ≤ y
2
if x > y
3
if x < y
4
if x = y or the relationship cannot be established.
5
if x ≥ y