ABC is a triangle, right angled at C. If BC = a, AB = c, and ‘p’ is the length of the perpendicular from C to AB. If AC = 2 BC then ‘c’ in terms of ‘a’ and ‘p’ =
1
\(\rm \frac{4p^2}{a}\)
2
\(\rm \frac{2a^2}{p}\)
3
\(\rm \frac{a}{p}\)
4
\(\rm \frac{2a}{p^2}\)