Find the solution of \(\frac{{8x}}{{15}} + 3x = \left( {\left( {x - 3} \right)\times- 3} \right) + \frac{{2x-3}}{{15}}\).

1
\(\frac{11}{8}\)
2
\(\frac{9}{7}\)
3
\(\frac{3}{11}\)
4
\(\frac{15}{4}\)

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