In ΔABC, D and E are points on the sides BC and AB, respectively, such that ∠ACB = ∠DEB. If AB = 12 cm, BE = 5 cm an BD ∶ CD = 1 ∶ 2, then BC is equal to:

1
\(8\sqrt{3}\) cm
2
\(5\sqrt{5}\) cm
3
\(6\sqrt{5}\) cm
4
\(6\sqrt{3}\) cm

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