In box M there are 22 white stones, x blue stones and 8 red stones. The probability of getting one white stone from box M is 11/20. Now, there is another box N which has (x + 2) white stones, (x + 5) blue stones and (x + 3) red stones. If one stone is selected from box N, then what will be the probability of the stone not being a red stone?
1
10/20
2
27/40
3
8/40
4
8/20
5
9/20