Comprehension Passage
Directions: Study the following information carefully and answer the related questions.
Five containers P, Q, R, S, and T hold a combination of three chemicals: Butane, Methanol, and Propanal. The aggregate volume of Butane and Methanol in all these containers is (4 + 6β - 100) milliliters. Of this, container P contains 18.75%, container Q has 6.25% and container R holds 31.25% of the Butane and Methanol mix. The total volume of the mixture in containers Q, R, and T is (β - 100) milliliters, (2 + 2β) milliliters, and (4 - β) milliliters, respectively. Whereas, the total volume of the mixture in container P is 100 milliliters more than what's present in container T. Additionally, the total volumes of the mixture in containers R and S are the same. The proportions of Butane to Methanol in containers P, Q, and R are 2:3, 5:4, and 1:2 respectively. The volumes of Propanal in containers S and T are (2β - 25) milliliters and ( + 100) milliliters respectively. The volumes of Butane in containers S and T are ( + 50) milliliters and (β + 150) milliliters respectively. Furthermore, container P has 30 milliliters more Methanol than what's contained in container S. The combined volume of Methanol and Propanal in container Q is 16.67% of the total volume of Methanol and Propanal in container T.

A volume of 100 milliliters of the mixture from container Q, 240 milliliters from container R, and 400 milliliters from container S is extracted and transferred into a new Beaker H. Afterward, 555 milliliters of the mixture in Beaker H is discarded and it is then replenished with 17.5 milliliters of Butane and 10 milliliters of Methanol. The question is, what is the ratio of Butane to Methanol in Beaker H's final mixture?

1
1:1
2
1:3
3
7:13
4
13:8
5
9:5

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