যদি \(\rm \displaystyle\int \dfrac{1}{\sqrt{9-16x^2}}dx=\alpha \sin^{-1} (\beta x)+c\) হয় তবে \(\rm \alpha + \dfrac{1}{\beta}=\)

1
1
2
\(\dfrac{7}{12}\)
3
\(\dfrac{19}{12}\)
4
\(\dfrac{9}{12}\)

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