রাশিমালার সরলীকরণে:

\(Y = \overline {\left( {A.B + \bar C} \right)\left( {\overline {A + B} + C} \right)} \)  বুলিয়ান বীজগণিত ব্যবহার করে, সমাধান হল:

1
(A. B + C) (A + B। C)
2
(A̅ + B̅ + C̅ ) (A + B + C)
3
(A. B + C̅ ) ( A. C + B̅ )
4
(B. C + A̅ ) (A. B + C̅ )

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