\(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} = \sqrt {1 - {{\rm{x}}^2} - {{\rm{y}}^2} + {{\rm{x}}^2}{{\rm{y}}^2}} \) এর সমাধান কী হবে?

1
sin -1 y = sin -1 x + c
2
\(2{\sin ^{ - 1}}{\rm{y}} = \sqrt {1 - {{\rm{x}}^2}} + {\sin ^{ - 1}}{\rm{x}} + {\rm{c}}\)
3
\(2{\sin ^{ - 1}}{\rm{y}} = {\rm{x}}\sqrt {1 - {{\rm{x}}^2}} + {\sin ^{ - 1}}{\rm{x}} + {\rm{c}}\)
4
\(2{\sin ^{ - 1}}{\rm{y}} = {\rm{x\;}}\sqrt {1 - {{\rm{x}}^2}} + {\cos ^{ - 1}}{\rm{x}} + {\rm{c}}\)

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