যদি sec θ = 5x এবং tan θ = \(\frac{5}{x}\) , তাহলে \(10\left(x^2-\frac{1}{x^2}\right)\) এর মান হল:

1
\(\frac{2}{5}\)
2
\(\frac{1}{5}\)
3
2
4
\(\frac{3}{5}\)

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